Cubic capacity of a cube found by multiplying the three dimensions together.
Cubic capacity of a cylinder = area of base × height.
Cubic capacity of a cone or pyramid = area of base × 1∕3 height.
Cubic capacity of a dome = area of base (circle) x 2∕3 height.
Cubic capacity of a sphere = D^3 x ·5236.
Area of segment of a circle found by adding to 2∕3 of product of chord and height, the cube of the height divided by twice the chord.
_Give the dimensions of a circular ward for 12 patients, each to have 1,750 cubic feet of available air-space._
Capacity of ward = 1,750 X 12 = 21,000 cubic feet.
If we allow 120 square feet floor-space for each patient, then the total floor-space will be 1,440 square feet. Consequently the height of the ward = 21000∕1440 = 14·75 feet.
The dimensions of the circular ward required are therefore a height of 14·75 feet, diameter of 43·2 feet, and circumference of 135·7 feet.
_Find the cubic capacity of a circular hospital ward 28 feet in diameter, 10 feet high, and with a dome-shaped roof 5 feet high._
Cubic capacity of the cylinder below the dome is 614·8 x 10 = 6,148 cubic feet.
Cubic capacity of dome = 614·8 x 2∕3 x 5 = 2049·3 cubic feet.
Total cubic capacity of the ward = 8197·3 cubic feet.
In practical measurements of rooms, deductions must be made from the cubic space for the furniture contained in it and for its inmates. About 10 cubic feet ought to be allowed for each bed and bedding, and 2½ to 4 cubic feet for each individual. Projecting surfaces must be allowed for by subtraction, and recesses by addition.
_A circular ward with a diameter of 36 feet has a dome-shaped roof, the height of whose centre is 18 feet. The height to the dome is 12 feet. Find the floor-space and total cubic contents. How many patients ought the ward to accommodate?_
Cubic capacity of cylinder below dome = 1017·87 x 12 = 12214·5 cubic feet.
Cubic capacity of dome = 1017·87 x 2∕3 x 6 = 4071·48 cubic feet.
Total cubic capacity of the ward = 16285·98 cubic feet.
Assuming that 1,500 cubic feet are required for each patient, then the ward is large enough for 10 _patients_. It is well to test this conclusion by calculating whether sufficient floor-space has been allowed for each patient. The floor-space has been found to be about 1,018 square feet, which would give 100 feet for each of 10 patients and more than the minimum standard previously stated.